Example: Add up the numbers from 1 to 100.
There is a nice way to do this by writing the sum in two ways, adding them up and dividing by 2.
\begin{array}{llllll} 1&+2&+3&+4&+\cdots &+100\\ 100&+99&+98&+97&+\cdots &+ 1\\\hline 101&+101&+101&+101&+\cdots &+ 101 \end{array}
Noting that 101 occurs 100 times these add up to 100\times 101.
Hence the sum
1+2+3+4+\cdots +100=\displaystyle {100\times 101 \over 2}
Did you notice that the first and last terms of the series add up to 101. This is how the general case works too.
Sum of an Arithmetic Series
The sum of the arithmetic series with n terms
A+ (A+d) + (A+2d)+\cdots + L
is
S_n={n(A+L)\over 2}
where
A= the first term
L= the last term
n= the number of terms in the series
L= the last term
For the example above,
A=1, L=100 and n=100 (and d=1 but we didn't need it here).
A=1, L=100 and n=100 (and d=1 but we didn't need it here).
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