Secondary Math Blogaroony: Show that the integral does NOT converge. $$\displaystyle \int_0^\infty {x^3\over (x^2-1)^2}$$

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Friday, 4 December 2015

Show that the integral does NOT converge. $\displaystyle \int_0^\infty {x^3\over (x^2-1)^2}$

Show that the integral does NOT converge.

$\displaystyle \int_0^\infty {x^3\over (x^2-1)^2}$

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