Secondary Math Blogaroony: Show that the integral does NOT converge. $$\displaystyle \int_0^\infty {x^3\over (x^2-1)^2}$$

Friday, 4 December 2015

Show that the integral does NOT converge. $$\displaystyle \int_0^\infty {x^3\over (x^2-1)^2}$$

Show that the integral does NOT converge.

$$\displaystyle \int_0^\infty {x^3\over (x^2-1)^2}$$

No comments:

Post a Comment

Subscribe to: Post Comments (Atom)