QUESTION(Quadratic Equations) Solve the equation $$(x+7)^2=64$$

QUESTION(Quadratic Equations)
Solve the equation
$$(x+7)^2=64$$

SOLUTION: ===============
Starting with   $(x+7)^2=64$ 
Take square roots of both sides to give 
$x+7 =  \pm \sqrt{64} $
$x+7 =  \pm 8 $
$x=  -7 \pm 8 $
$x = -7-8  or -7 + 8 $
$x = -15, 1 $

[  CHECK: 
when $x=-15$, 
LHS $= (x+7)^2 = (-15 + 7)^2 = (-8)^2 = 64 = $ RHS.
when $x = 1$, 
LHS $= (x+7)^2 = (1 + 7)^2 = (8)^2 = 64 =$ RHS.  ]