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Saturday, 5 December 2015

Quadratic function. An object is thrown upward from a height of 50 feet with an initial velocity of 48 ft/s.

QUESTION

SOLUTION
(a)
h=-16(3)^2+48(3)+50
=50 ft

(b) 
Since when t=0, h=50, and when t=3, h=50 also, 
by symmetry the highest point is reached half way in between, so t=(0+3)/2=1.5s

Therefore the maximum height is 
h=-16(1.5)^2+48(1.5)+50
=86 ft



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