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Showing posts with label Asymptotes. Show all posts
Showing posts with label Asymptotes. Show all posts
Friday, 6 November 2015
Friday, 9 December 2005
Concept check. Match the rational function with the aspect described.
ANSWERS
A 36
B 30
C 34
D 29
E 33
F 35
G 31
H 32
Sunday, 20 March 2005
For these rational functions: find asymptotes, sketch as indicated.
Questions.
Give the equation of any horizontal, vertical, or oblique asymptotes.
Q38. $f(x)=\displaystyle -{6\over x+9}$
Q42. $f(x)=\displaystyle {x^2+4\over x-1}$
Sketch
Q52. $f(x)=\displaystyle {x-5\over x+3}$
Q54. $f(x)=\displaystyle {2x+1\over x^2+6x+8}$
Q62. $f(x)=\displaystyle {x^2-7x+10\over x^2+9}$
Q64. $f(x)=\displaystyle {2x^2+3\over x-4}$
Q68. $f(x)=\displaystyle {x^2-16\over x+4}$
SOLUTIONS ======
Q38. Vertical asymptotes is $x=-9$, horizontal asymptotes is $y=0$.
Give the equation of any horizontal, vertical, or oblique asymptotes.
Q38. $f(x)=\displaystyle -{6\over x+9}$
Q42. $f(x)=\displaystyle {x^2+4\over x-1}$
Sketch
Q52. $f(x)=\displaystyle {x-5\over x+3}$
Q54. $f(x)=\displaystyle {2x+1\over x^2+6x+8}$
Q62. $f(x)=\displaystyle {x^2-7x+10\over x^2+9}$
Q64. $f(x)=\displaystyle {2x^2+3\over x-4}$
Q68. $f(x)=\displaystyle {x^2-16\over x+4}$
SOLUTIONS ======
Q38. Vertical asymptotes is $x=-9$, horizontal asymptotes is $y=0$.
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