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Saturday, 21 November 2015

GROVE PRELIM 2U/3U TEST YOURSELF 8 - Q18

y={1\over 3}x^{-1}
y'=-{1\over 3}x^{-2}
y'=-{1\over 3x^2}

y'=-{1\over 3\left({1\over 6}\right)^2}=-{36\over 3}=-12

When x=1/6, y=1/(3(1/6))=2

y-2=-12(x-1/6)
y-2=-12x+2
12x+y-4=0

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