Regarding $\pi$ as a constant and differentiating with respect to $x$.
$${dS\over dr}=2\times 4\pi r^{2-1}$$
$${dS\over dr}=8\pi r^{1}$$
$${dS\over dr}=8\pi r$$
C'est fini.
JH
This blog goes back a few years! while I was teaching in various schools in NSW, Australia. It contains a wide range of mathematics explanations, notes, and resources covering secondary-level mathematics topics. The easiest ways to navigate are by using the search bar or browsing through the labels/tags. If you find my content helpful and would like to support my work, a coffee donation is greatly appreciated — thank you!
No comments:
Post a Comment