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Wednesday, 28 October 2015

GROVE HSC 2U EX 2.6 Q5 POINT OF INFLEXION

QUESTION: Show that the curve f(x)=2x^3-5 has an inflexion and find its coordinates.

f'(x)=6x^2
f''(x)=12x

For possible inflexions: solve f''(x)=0.

12x=0
\therefore x=0.
When x=0, f(0)=2(0)^3-5=-5.

So, possible inflexion is (0,-5).

Check concavity to verify inflexion.



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PS. the graph wasn't asked for but here it is anyway :-)

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