QUESTION: Show that the curve f(x)=2x^3-5 has an inflexion and find its coordinates.
f'(x)=6x^2
f''(x)=12x
For possible inflexions: solve f''(x)=0.
12x=0
\therefore x=0.
When x=0, f(0)=2(0)^3-5=-5.
So, possible inflexion is (0,-5).
Check concavity to verify inflexion.
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PS. the graph wasn't asked for but here it is anyway :-)
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