Give the equation of any horizontal, vertical, or oblique asymptotes.
Q38. f(x)=\displaystyle -{6\over x+9}
Q42. f(x)=\displaystyle {x^2+4\over x-1}
Sketch
Q52. f(x)=\displaystyle {x-5\over x+3}
Q54. f(x)=\displaystyle {2x+1\over x^2+6x+8}
Q62. f(x)=\displaystyle {x^2-7x+10\over x^2+9}
Q64. f(x)=\displaystyle {2x^2+3\over x-4}
Q68. f(x)=\displaystyle {x^2-16\over x+4}
SOLUTIONS ======
Q38. Vertical asymptotes is x=-9, horizontal asymptotes is y=0.
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