Consider the two points A(x_1, y_1) \quad\mbox{and}\quad B(x_2, y_2)
The distance between the points A and B is d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\quad\quad\quad \mbox{DISTANCE}
The coordinates of the midpoint of the interval joining the points A and B are \left( {x_1+x_2 \over 2 }, {y_1+y_2 \over 2}\right)\quad\quad\quad \mbox{MIDPOINT}
The slope or gradient of the line through the points A and B is m={y_2-y_1 \over x_2-x_1 }={ \mbox{rise}\over \mbox{run}}\quad\quad\quad \mbox{GRADIENT}
The GRADIENT-INTERCEPT form of the equation of a line is y=mx+b where m is the gradient or slope of the line, and b is the y-intercept.
The POINT-GRADIENT form of a line is y-y_1=m(x-x_1) where m is the gradient of the line, and (x_1,y_1) is ANY point on the line.
The GENERAL FORM OF A LINE is ax+by+c=0 where a,b,c are constants.The slopes or gradients of parallel lines are equal, that is, m_1=m_2.
The slopes of perpendicular lines are negative reciprocals of each other. This can be written as m_2=-{1\over m_1}\quad\quad\mbox{or}\quad\quad m_1\times m_2=-1
The x-intercept is found by putting y=0 and solving for x in the equation of the line. The y-intercept is found by putting x=0 and solving for y in the equation of the line.
VERTICAL LINES have the form, x=k where k is a constant (number).
HORIZONTAL LINES have the form, y=k where k is a constant (number). }
The distance between the points A and B is d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\quad\quad\quad \mbox{DISTANCE}
The coordinates of the midpoint of the interval joining the points A and B are \left( {x_1+x_2 \over 2 }, {y_1+y_2 \over 2}\right)\quad\quad\quad \mbox{MIDPOINT}
The slope or gradient of the line through the points A and B is m={y_2-y_1 \over x_2-x_1 }={ \mbox{rise}\over \mbox{run}}\quad\quad\quad \mbox{GRADIENT}
The GRADIENT-INTERCEPT form of the equation of a line is y=mx+b where m is the gradient or slope of the line, and b is the y-intercept.
The POINT-GRADIENT form of a line is y-y_1=m(x-x_1) where m is the gradient of the line, and (x_1,y_1) is ANY point on the line.
The GENERAL FORM OF A LINE is ax+by+c=0 where a,b,c are constants.The slopes or gradients of parallel lines are equal, that is, m_1=m_2.
The slopes of perpendicular lines are negative reciprocals of each other. This can be written as m_2=-{1\over m_1}\quad\quad\mbox{or}\quad\quad m_1\times m_2=-1
The x-intercept is found by putting y=0 and solving for x in the equation of the line. The y-intercept is found by putting x=0 and solving for y in the equation of the line.
VERTICAL LINES have the form, x=k where k is a constant (number).
HORIZONTAL LINES have the form, y=k where k is a constant (number). }
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