Give the equation of any horizontal, vertical, or oblique asymptotes.
Q38. $f(x)=\displaystyle -{6\over x+9}$
Q42. $f(x)=\displaystyle {x^2+4\over x-1}$
Sketch
Q52. $f(x)=\displaystyle {x-5\over x+3}$
Q54. $f(x)=\displaystyle {2x+1\over x^2+6x+8}$
Q62. $f(x)=\displaystyle {x^2-7x+10\over x^2+9}$
Q64. $f(x)=\displaystyle {2x^2+3\over x-4}$
Q68. $f(x)=\displaystyle {x^2-16\over x+4}$
SOLUTIONS ======
Q38. Vertical asymptotes is $x=-9$, horizontal asymptotes is $y=0$.
