QUESTIONS DONE: Q6, 8, 10b, 14, 22, 23,
Q6 =========================
Q8 ==============
Q10b =========================
Q14 =========================
Q22 =========================
Q23 =========================
SEARCH THIS BLOG :-)
Sunday, 10 December 2006
Tuesday, 5 December 2006
Inverse functions - Sketch the graph of the inverse function
Let $f(x)=2x^2-7x+5$ and $g(x)=3x-3$. Find $(f\circ g)(2)$ and $(g\circ f)(-1)$.
QUESTION
Let $f(x)=2x^2-7x+5$ and $g(x)=3x-3$. Find $(f\circ g)(2)$ and $(g\circ f)(-1)$.
SOLUTION
Jan Hansen
Let $f(x)=2x^2-7x+5$ and $g(x)=3x-3$. Find $(f\circ g)(2)$ and $(g\circ f)(-1)$.
SOLUTION
Jan Hansen
Sunday, 2 July 2006
SOLUTIONS TO 1997 COLLEGE ENTRANCE EXAM - mostly Calculus, Differentiation, Integration, Areas, Volumes.
SOLUTIONS TO 1997 COLLEGE ENTRANCE EXAM - mostly Calculus, Differentiation, Integration, Areas, Volumes.
Here are the questions. Then follow my solutions :-)
SOLUTIONS ===================
Here are the questions. Then follow my solutions :-)
SOLUTIONS ===================
Labels:
Area between two curves,
BOSTES,
Calculus,
College Entrance Exam,
concavity,
Differentiation,
high school,
implicit differentiation,
Integration,
reverse chain rule,
volume of revolution
Thursday, 1 June 2006
1. Consider the partial differential equation: $\displaystyle q(x) { \partial u\over \partial t}={ \partial \over \partial x} \left( p(x) { \partial u\over \partial x} \right)$ (a) Confirm that $$U(x) = A +(B-A){\int_0^x p(s)^{-1} ds\over \int_0^L p(s)^{-1} ds }$$ Is a solution of the partial differential equation (b) Confirm that if $u=U+v$ then $v$ indeed satisfies the partial differential equation if $u$ does (c) Confirm that $X(x)T(t)$ is indeed a solution of the partial diff eq if $X$ and $T$ are solutions of the following respectively: $${d\over dx} \left(p(x) {dX\over dx}\right) – kq(x)X = 0$$ $${dT\over dt} = kT$$ where $k$ is a constant
1. Consider the
partial differential equation:
$\displaystyle q(x) { \partial u\over \partial t}={ \partial \over \partial x} \left( p(x) { \partial u\over \partial x} \right)$
$\displaystyle q(x) { \partial u\over \partial t}={ \partial \over \partial x} \left( p(x) { \partial u\over \partial x} \right)$
(a) Confirm that
$$U(x) = A +(B-A){\int_0^x p(s)^{-1} ds\over \int_0^L p(s)^{-1} ds }$$
Is a solution of the partial differential equation
(b) Confirm that if $u=U+v$ then $v$ indeed satisfies the
partial differential equation if $u$ does
(c) Confirm that $X(x)T(t)$ is indeed a solution of the
partial diff eq if $X$ and $T$ are solutions of the following respectively:
$${d\over dx} \left(p(x) {dX\over dx}\right) – kq(x)X = 0$$
$${dT\over dt} = kT$$
where $k$ is a constant
SOLUTION ===============
Wednesday, 1 March 2006
QUESTION. Let $L:V\rightarrow W$ be a linear map. Let $w$ be an element of $W$. Let $\nu_0$ be an element of $V$ such that $L(\nu_0)=w$. Show that any solution of the equation $L(X)=w$ is a type $\nu_0+u$. where $u$ is an element of the kernel of $D$.
QUESTION. Let $L:V\rightarrow W$ be a linear map. Let $w$ be an element of $W$. Let $\nu_0$ be an element of $V$ such that $L(\nu_0)=w$. Show that any solution of the equation $L(X)=w$ is a type $\nu_0+u$. where $u$ is an element of the kernel of $D$.
Labels:
Linear map,
University undergraduate,
Vector space
Monday, 20 February 2006
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